Combined+Gas+Law

Evan N, Christian M, Logan B, Matt S

Combined Gas Laws

Formula: Example Problems:

Problem 1: A cylinder contain a gas of volume 30 L, at a pressure of 110 kPa and a temperature of 420 K. Find the temperature of the gas which has a volume 40 L at a pressure of 120 kPa. Vi = 30 L, Pi = 110 kPa, Ti = 420 K, Vf = 40 L, Pf = 120 kPa Step 1: Substitute the values in the below final temperature equation: Final Temperature(Tf) = PfVfTi / PiVi = (120 x 40 x 420) / (110 x 30) = 2016000 / 3300 Final Temperature(Tf) = 610.91 K This example will guide you to calculate the final temperature manually.

Problem 2: A cylinder contain a gas of volume 10 L, at a pressure of 80 kPa and a temperature of 200 K. Find the temperature of the gas which has a volume 20 L at a temperature of 220 K. Vi = 10 L, Pi = 80 kPa, Ti = 200 K, Vf = 20 L, Tf = 220 kPa Step 1: Substitute the values in the below pressure equation: Final Pressure(Pf) = PiViTf / TiVf = (80 x 10 x 220) / (200 x 20) = 176000 / 4000 Final Pressure(Vf) = 44 kPa This example will guide you to calculate the pressure manually.

Molecule explanation:

 * 1) If temperature and pressure are kept constant, then the volume of the gas is directly proportional to the number of molecules of gas.
 * 2) If the temperature and volume remain constant, then the pressure of the gas changes is directly proportional to the number of molecules of gas present.
 * 3) If the number of gas molecules and the temperature remain constant, then the pressure is inversely proportional to the volume.
 * 4) If the temperature changes and the number of gas molecules are kept constant, then either pressure or volume (or both) will change in direct proportion to the temperature.

of both Boyle's Law and Charles's Law:**
 * Here is the relationship between the different gas laws. Combined gas law is a combination



Websites:
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